s.esmaeiliandClaude Opus 4.6
19d490e790
- Add Tahesab/Zarrin accounting sync module with admin panel UI - Add SMS relay driver as default provider, refactor SMS into driver pattern - Update customer services, orders, products, and catalog queries - Rebuild user-app and user-app-v2 dist assets - Add Prisma migration for accounting tables - Update docker-compose and env examples - Update parity docs (DECISIONS, ISSUES, PROGRESS) Co-Authored-By: Claude Opus 4.6 <noreply@anthropic.com>
322 lines
18 KiB
SQL
322 lines
18 KiB
SQL
-- ============================================================================
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-- پیش‌بررسی مهاجرت — فقط شمارش، صفر داده
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-- ============================================================================
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--
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-- روی دیتابیس MySQL قدیمی (اسکیمای `oapi`) اجرا شود.
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--
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-- ⚠️ این فایل فقط SELECT COUNT / SUM / MIN / MAX دارد.
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-- هیچ INSERT / UPDATE / DELETE / DROP / ALTER در آن نیست.
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-- هیچ ستون متنی (نام، موبایل، کد ملی، آدرس) در خروجی ظاهر نمی‌شود.
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--
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-- اجرا:
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-- mysql -u USER -p -h HOST -P 3305 oapi < migration-precheck.sql > out.txt
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--
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-- سپس محتوای out.txt کپی شود. خروجی فقط عدد است.
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--
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-- مرجع: docs/DATA-MIGRATION-MAP.md §۳ · §۵.۳ · §۵.۵ · §۵.۶
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-- ============================================================================
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-- ---------------------------------------------------------------------------
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-- بخش ۱ — حجم کار: تعداد ردیف زنده و حذف‌شده‌ی نرم
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-- مرجع: §۵.۶ — ردیف حذف‌شده نباید منتقل شود
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-- ---------------------------------------------------------------------------
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SELECT '=== 1. ROW COUNTS ===' AS section;
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SELECT 'customers' AS tbl, COUNT(*) AS live, SUM(deleted_at IS NOT NULL) AS soft_deleted FROM customers
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UNION ALL SELECT 'users', COUNT(*), SUM(deleted_at IS NOT NULL) FROM users
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UNION ALL SELECT 'orders', COUNT(*), SUM(deleted_at IS NOT NULL) FROM orders
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UNION ALL SELECT 'order_items', COUNT(*), SUM(deleted_at IS NOT NULL) FROM order_items
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UNION ALL SELECT 'cashes', COUNT(*), SUM(deleted_at IS NOT NULL) FROM cashes
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UNION ALL SELECT 'product', COUNT(*), SUM(deleted_at IS NOT NULL) FROM product
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UNION ALL SELECT 'variant', COUNT(*), SUM(deleted_at IS NOT NULL) FROM products_productvarient
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UNION ALL SELECT 'prod_image', COUNT(*), SUM(deleted_at IS NOT NULL) FROM products_productimage
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UNION ALL SELECT 'category', COUNT(*), SUM(deleted_at IS NOT NULL) FROM category_collection
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UNION ALL SELECT 'image', COUNT(*), SUM(deleted_at IS NOT NULL) FROM image
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UNION ALL SELECT 'cities', COUNT(*), SUM(deleted_at IS NOT NULL) FROM cities
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UNION ALL SELECT 'branches', COUNT(*), SUM(deleted_at IS NOT NULL) FROM branches
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UNION ALL SELECT 'workshops', COUNT(*), SUM(deleted_at IS NOT NULL) FROM workshops
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UNION ALL SELECT 'custom_orders', COUNT(*), SUM(deleted_at IS NOT NULL) FROM custom_orders
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UNION ALL SELECT 'comments', COUNT(*), SUM(deleted_at IS NOT NULL) FROM comments
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UNION ALL SELECT 'messages', COUNT(*), 0 FROM messages
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UNION ALL SELECT 'notify', COUNT(*), SUM(deleted_at IS NOT NULL) FROM notify
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UNION ALL SELECT 'fav', COUNT(*), 0 FROM fav
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UNION ALL SELECT 'permission', COUNT(*), 0 FROM permission
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UNION ALL SELECT 'config_statics', COUNT(*), SUM(deleted_at IS NOT NULL) FROM config_statics;
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-- ---------------------------------------------------------------------------
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-- بخش ۲ — 🔴 یکتایی: آیا @unique در Prisma می‌شکند؟
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-- مرجع: §۳ — مبدأ هیچ unique index ندارد
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-- هر عدد غیرصفر یعنی مهاجرت در میانه متوقف می‌شود
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-- ---------------------------------------------------------------------------
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SELECT '=== 2. UNIQUENESS (any nonzero = migration breaks) ===' AS section;
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-- چند *گروه* موبایل تکراری، و چند ردیف درگیرند
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SELECT 'dup_mobile_groups' AS metric, COUNT(*) AS n FROM (
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SELECT mobile FROM customers
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WHERE deleted_at IS NULL AND mobile IS NOT NULL AND mobile <> ''
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GROUP BY mobile HAVING COUNT(*) > 1
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) d
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UNION ALL
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SELECT 'dup_mobile_rows', COALESCE(SUM(c),0) FROM (
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SELECT COUNT(*) AS c FROM customers
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WHERE deleted_at IS NULL AND mobile IS NOT NULL AND mobile <> ''
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GROUP BY mobile HAVING COUNT(*) > 1
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) d2
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UNION ALL
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SELECT 'dup_ncode_groups', COUNT(*) FROM (
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SELECT ncode FROM customers
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WHERE deleted_at IS NULL AND ncode IS NOT NULL AND ncode <> ''
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GROUP BY ncode HAVING COUNT(*) > 1
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) d3
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UNION ALL
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SELECT 'dup_ncode_rows', COALESCE(SUM(c),0) FROM (
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SELECT COUNT(*) AS c FROM customers
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WHERE deleted_at IS NULL AND ncode IS NOT NULL AND ncode <> ''
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GROUP BY ncode HAVING COUNT(*) > 1
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) d4;
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-- تهی‌بودن: Prisma هر دو را NOT NULL می‌خواهد
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SELECT 'empty_mobile' AS metric, SUM(mobile IS NULL OR mobile = '') AS n FROM customers WHERE deleted_at IS NULL
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UNION ALL SELECT 'empty_ncode', SUM(ncode IS NULL OR ncode = '') FROM customers WHERE deleted_at IS NULL;
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-- تداخل شماره بین مشتری و کاربر ادمین (D21: «کارشناس برنده است»)
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SELECT 'mobile_collision_customer_vs_user' AS metric, COUNT(*) AS n
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FROM customers c JOIN users u ON u.mobile = c.mobile
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WHERE c.deleted_at IS NULL AND u.deleted_at IS NULL
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AND c.mobile IS NOT NULL AND c.mobile <> '';
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-- یکتایی در جدول users هم بررسی شود
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SELECT 'dup_user_mobile_groups' AS metric, COUNT(*) AS n FROM (
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SELECT mobile FROM users
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WHERE deleted_at IS NULL AND mobile IS NOT NULL AND mobile <> ''
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GROUP BY mobile HAVING COUNT(*) > 1
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) d;
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-- ---------------------------------------------------------------------------
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-- بخش ۳ — 🔴 نام: آیا D0 درست است؟
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-- مرجع: §۲ — fname/lname از قبل وجود دارند
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-- ---------------------------------------------------------------------------
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SELECT '=== 3. NAME PARTS (does `name` agree with fname+lname?) ===' AS section;
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SELECT
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SUM(fname IS NULL OR fname = '') AS empty_fname,
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SUM(lname IS NULL OR lname = '') AS empty_lname,
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SUM(name IS NULL OR name = '') AS empty_name,
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-- ردیف‌هایی که name با اجزا نمی‌خواند → trigger مقصد name را بازنویسی می‌کند
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SUM(TRIM(COALESCE(name,'')) <> TRIM(CONCAT(COALESCE(fname,''),' ',COALESCE(lname,'')))) AS name_mismatch,
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-- اجزا تهی ولی name پر → تنها حالتی که تجزیه لازم است
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SUM((fname IS NULL OR fname = '') AND (lname IS NULL OR lname = '')
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AND name IS NOT NULL AND name <> '') AS parts_empty_name_set
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FROM customers WHERE deleted_at IS NULL;
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-- ---------------------------------------------------------------------------
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-- بخش ۴ — enum ها: آیا مقداری بی‌نگاشت می‌ماند؟
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-- مرجع: §۵.۳ (type) · §۵.۵ (verify) · §۷.۳ (sts)
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-- ---------------------------------------------------------------------------
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SELECT '=== 4. ENUMS ===' AS section;
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-- type: 1..5 نگاشت دارند. NULL یا خارج از بازه → بی‌صدا APP_SHOPKEEPER می‌شود
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SELECT 'customers.type' AS col, CAST(type AS CHAR) AS val, COUNT(*) AS n
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FROM customers WHERE deleted_at IS NULL GROUP BY type ORDER BY type;
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-- sts و active: دو سوییچ مجزا
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SELECT 'customers.sts' AS col, CAST(sts AS CHAR) AS val, COUNT(*) AS n
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FROM customers WHERE deleted_at IS NULL GROUP BY sts
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UNION ALL
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SELECT 'customers.active', CAST(active AS CHAR), COUNT(*)
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FROM customers WHERE deleted_at IS NULL GROUP BY active
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UNION ALL
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SELECT 'customers.is_archive', CAST(is_archive AS CHAR), COUNT(*)
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FROM customers WHERE deleted_at IS NULL GROUP BY is_archive;
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-- دو ستون تأیید → یک enum چهارحالته. حالت (0,1) در مقصد نماینده ندارد
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SELECT 'verify_step_combo' AS col,
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CONCAT(COALESCE(CAST(sts_verify_step_one AS CHAR),'NULL'), ',',
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COALESCE(CAST(sts_verify_step_two AS CHAR),'NULL')) AS val,
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COUNT(*) AS n
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FROM customers WHERE deleted_at IS NULL
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GROUP BY sts_verify_step_one, sts_verify_step_two;
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-- وضعیت سفارش عمده: 0..6 نگاشت دارند
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SELECT 'orders.sts' AS col, CAST(sts AS CHAR) AS val, COUNT(*) AS n
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FROM orders WHERE deleted_at IS NULL GROUP BY sts ORDER BY sts;
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-- اسناد مالی: type → LedgerSourceType (9,1,2,3,4)، confirmed حیاتی است (D24)
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SELECT 'cashes.type' AS col, CAST(type AS CHAR) AS val, COUNT(*) AS n
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FROM cashes WHERE deleted_at IS NULL GROUP BY type ORDER BY type;
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SELECT 'cashes.confirmed' AS col, CAST(confirmed AS CHAR) AS val, COUNT(*) AS n
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FROM cashes WHERE deleted_at IS NULL GROUP BY confirmed;
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-- ---------------------------------------------------------------------------
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-- بخش ۵ — 🔴 پول و وزن: مبنای تطبیق + تأیید اینکه آستانه لازم است
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-- مرجع: §۴ — ۱۱۰ ستون double، «صفر اختلاف» دست‌نیافتنی است
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-- ---------------------------------------------------------------------------
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SELECT '=== 5. MONEY / WEIGHT TOTALS (migration must match these) ===' AS section;
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SELECT
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COUNT(*) AS n_customers,
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CAST(SUM(remain) AS CHAR) AS sum_gold_debt,
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CAST(SUM(rial_remain) AS CHAR) AS sum_rial_debt,
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CAST(SUM(gram_level) AS CHAR) AS sum_credit_limit,
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SUM(remain <> 0) AS n_nonzero_gold,
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SUM(rial_remain <> 0) AS n_nonzero_rial,
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SUM(remain < 0) AS n_negative_gold,
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SUM(rial_remain < 0) AS n_negative_rial
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FROM customers WHERE deleted_at IS NULL;
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-- 🔴 شاهدِ مشکل double: چند ردیف مقداری دارند که در Decimal(14,4) جا نمی‌شود؟
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-- عدد غیرصفر = گِردکردن رخ می‌دهد = «صفر اختلاف» ناممکن است
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SELECT 'gold_needs_rounding' AS metric, SUM(remain <> ROUND(remain, 4)) AS n
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FROM customers WHERE deleted_at IS NULL
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UNION ALL
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SELECT 'credit_needs_rounding', SUM(gram_level <> ROUND(gram_level, 4))
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FROM customers WHERE deleted_at IS NULL
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UNION ALL
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SELECT 'order_weight_needs_rounding', SUM(w <> ROUND(w, 4))
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FROM orders WHERE deleted_at IS NULL
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UNION ALL
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SELECT 'cash_amount_needs_rounding', SUM(remain <> ROUND(remain, 4))
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FROM cashes WHERE deleted_at IS NULL;
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-- فقط اسناد تأییدشده در موجودی حساب می‌شوند (D24)
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SELECT 'confirmed_only' AS scope,
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CAST(SUM(remain) AS CHAR) AS sum_gold,
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CAST(SUM(rial_remain) AS CHAR) AS sum_rial,
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COUNT(*) AS n
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FROM cashes WHERE deleted_at IS NULL AND confirmed = 1;
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-- ---------------------------------------------------------------------------
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-- بخش ۶ — یکپارچگی ارجاعی (مبدأ صفر FK دارد — §۱۱)
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-- ارجاع یتیم = ردیفی که مهاجرت نمی‌تواند وصل کند
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-- ---------------------------------------------------------------------------
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SELECT '=== 6. ORPHAN REFERENCES (no FKs exist in source) ===' AS section;
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SELECT 'customer.city_id -> cities' AS ref, COUNT(*) AS orphans
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FROM customers c LEFT JOIN cities ci ON ci.id = c.city_id
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WHERE c.deleted_at IS NULL AND c.city_id IS NOT NULL AND ci.id IS NULL
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UNION ALL
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SELECT 'customer.reagent_id -> users', COUNT(*)
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FROM customers c LEFT JOIN users u ON u.id = c.reagent_id
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WHERE c.deleted_at IS NULL AND c.reagent_id IS NOT NULL AND u.id IS NULL
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UNION ALL
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SELECT 'customer.image_id -> image', COUNT(*)
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FROM customers c LEFT JOIN image i ON i.id = c.image_id
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WHERE c.deleted_at IS NULL AND c.image_id IS NOT NULL AND i.id IS NULL
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UNION ALL
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SELECT 'order.customer_id -> customers', COUNT(*)
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FROM orders o LEFT JOIN customers c ON c.id = o.customer_id
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WHERE o.deleted_at IS NULL AND o.customer_id IS NOT NULL AND c.id IS NULL
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UNION ALL
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SELECT 'order_items.order_id -> orders', COUNT(*)
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FROM order_items oi LEFT JOIN orders o ON o.id = oi.order_id
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WHERE oi.deleted_at IS NULL AND oi.order_id IS NOT NULL AND o.id IS NULL
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UNION ALL
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SELECT 'order_items.variant_id -> variant', COUNT(*)
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FROM order_items oi LEFT JOIN products_productvarient v ON v.id = oi.variant_id
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WHERE oi.deleted_at IS NULL AND oi.variant_id IS NOT NULL AND v.id IS NULL
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UNION ALL
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SELECT 'cashes.customer_id -> customers', COUNT(*)
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FROM cashes ca LEFT JOIN customers c ON c.id = ca.customer_id
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WHERE ca.deleted_at IS NULL AND ca.customer_id IS NOT NULL AND c.id IS NULL
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UNION ALL
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SELECT 'variant.product_id_id -> product', COUNT(*)
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FROM products_productvarient v LEFT JOIN product p ON p.id = v.product_id_id
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WHERE v.deleted_at IS NULL AND v.product_id_id IS NOT NULL AND p.id IS NULL
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UNION ALL
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SELECT 'fav.customer_id -> customers', COUNT(*)
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FROM fav f LEFT JOIN customers c ON c.id = f.customer_id
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WHERE c.id IS NULL
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UNION ALL
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SELECT 'fav.product_id -> product', COUNT(*)
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FROM fav f LEFT JOIN product p ON p.id = f.product_id
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WHERE p.id IS NULL;
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-- 🔴 fav هیچ PK ندارد → ردیف تکراری ممکن است (§۱۰)
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SELECT 'fav_duplicate_pairs' AS metric, COUNT(*) AS n FROM (
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SELECT customer_id, product_id FROM fav
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GROUP BY customer_id, product_id HAVING COUNT(*) > 1
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) d;
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-- permission هم PK ندارد
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SELECT 'permission_duplicate_rows' AS metric, COUNT(*) AS n FROM (
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SELECT rid, ut FROM permission GROUP BY rid, ut HAVING COUNT(*) > 1
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) d;
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-- ---------------------------------------------------------------------------
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-- بخش ۷ — ستون‌های مبهم: نوع واقعی داده
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-- مرجع: §۸ — ayar متنی یا عددی؟ تاریخ جلالی یا میلادی؟
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-- ---------------------------------------------------------------------------
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SELECT '=== 7. AMBIGUOUS COLUMNS ===' AS section;
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-- ayar در مبدأ varchar(20) است ولی مقصد Int? — مقدار غیرعددی می‌شکند
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SELECT 'ayar_total' AS metric, COUNT(*) AS n FROM cashes WHERE deleted_at IS NULL AND ayar IS NOT NULL AND ayar <> ''
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UNION ALL
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SELECT 'ayar_non_numeric', COUNT(*) FROM cashes
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WHERE deleted_at IS NULL AND ayar IS NOT NULL AND ayar <> '' AND ayar NOT REGEXP '^[0-9]+$';
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-- recive_date / proceed_at در مبدأ varchar هستند — جلالی یا میلادی؟
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-- طول رشته و اینکه با 13 یا 14 شروع می‌شود، نوع تقویم را لو می‌دهد
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SELECT 'recive_date_set' AS metric, COUNT(*) AS n FROM cashes WHERE deleted_at IS NULL AND recive_date IS NOT NULL AND recive_date <> ''
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UNION ALL
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SELECT 'recive_date_starts_13x', COUNT(*) FROM cashes WHERE deleted_at IS NULL AND recive_date LIKE '13%'
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UNION ALL
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SELECT 'recive_date_starts_14x', COUNT(*) FROM cashes WHERE deleted_at IS NULL AND recive_date LIKE '14%'
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UNION ALL
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SELECT 'recive_date_starts_20x', COUNT(*) FROM cashes WHERE deleted_at IS NULL AND recive_date LIKE '20%'
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UNION ALL
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SELECT 'proceed_at_set', COUNT(*) FROM cashes WHERE deleted_at IS NULL AND proceed_at IS NOT NULL AND proceed_at <> '';
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-- ستون‌های داده‌ی غیرقابل‌بازسازی (§۵.۲ گروه ج) — چند ردیف واقعاً مقدار دارند؟
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SELECT 'has_birth_date' AS metric, COUNT(*) AS n FROM customers WHERE deleted_at IS NULL AND birth_date IS NOT NULL
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UNION ALL SELECT 'has_marriage_date', COUNT(*) FROM customers WHERE deleted_at IS NULL AND marriage_date IS NOT NULL
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UNION ALL SELECT 'has_token_mobile', COUNT(*) FROM customers WHERE deleted_at IS NULL AND token_mobile IS NOT NULL AND token_mobile <> ''
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UNION ALL SELECT 'has_new_city', COUNT(*) FROM customers WHERE deleted_at IS NULL AND new_city IS NOT NULL AND new_city <> '';
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-- فرمت رمز عبور: bcrypt با $2y$ شروع می‌شود. اگر نه، hash دیگری است
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SELECT 'pw_bcrypt' AS metric, SUM(password LIKE '$2%') AS n FROM customers WHERE deleted_at IS NULL
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UNION ALL SELECT 'pw_other', SUM(password IS NOT NULL AND password <> '' AND password NOT LIKE '$2%') FROM customers WHERE deleted_at IS NULL
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UNION ALL SELECT 'pw_empty', SUM(password IS NULL OR password = '') FROM customers WHERE deleted_at IS NULL;
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-- ---------------------------------------------------------------------------
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-- بخش ۸ — جداول پشتیبان: آیا ردیفی دارند که `customers` ندارد؟
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-- مرجع: §۱.۱ — قبل از نادیده‌گرفتن باید شمرده شوند
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-- ---------------------------------------------------------------------------
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SELECT '=== 8. BACKUP TABLES (safe to ignore?) ===' AS section;
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SELECT 'customers' AS tbl, COUNT(*) AS n, CAST(MAX(id) AS CHAR) AS max_id FROM customers
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UNION ALL SELECT 'customers_copy1', COUNT(*), CAST(MAX(id) AS CHAR) FROM customers_copy1
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UNION ALL SELECT 'customers_copy2', COUNT(*), CAST(MAX(id) AS CHAR) FROM customers_copy2
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UNION ALL SELECT 'customers_test', COUNT(*), CAST(MAX(id) AS CHAR) FROM customers_test;
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-- شناسه‌هایی که در کپی هستند ولی در جدول اصلی نیستند → یعنی ردیف حذف شده
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SELECT 'ids_only_in_copy1' AS metric, COUNT(*) AS n
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FROM customers_copy1 k LEFT JOIN customers c ON c.id = k.id WHERE c.id IS NULL
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UNION ALL
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SELECT 'ids_only_in_copy2', COUNT(*)
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FROM customers_copy2 k LEFT JOIN customers c ON c.id = k.id WHERE c.id IS NULL;
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-- ---------------------------------------------------------------------------
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-- بخش ۹ — تک‌فروشی (به تأخیر افتاده، §۷.۲) — فقط حجم، برای برنامه‌ریزی آینده
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-- ---------------------------------------------------------------------------
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SELECT '=== 9. RETAIL (deferred — size only) ===' AS section;
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SELECT 'orders_orders' AS tbl, COUNT(*) AS live, SUM(deleted_at IS NOT NULL) AS soft_deleted FROM orders_orders
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UNION ALL SELECT 'orders_orderitem', COUNT(*), SUM(deleted_at IS NOT NULL) FROM orders_orderitem
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UNION ALL SELECT 'login', COUNT(*), SUM(deleted_at IS NOT NULL) FROM login;
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-- 🔴 sts=7 در خرده «تحویل مشتری» است ولی در عمده «کنسل». چند ردیف درگیرند؟
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SELECT 'retail_sts' AS col, CAST(sts AS CHAR) AS val, COUNT(*) AS n
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FROM orders_orders WHERE deleted_at IS NULL GROUP BY sts ORDER BY sts;
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SELECT '=== END ===' AS section;
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